Shweta Thakur posted an Question
August 02, 2020 • 23:03 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Plz explain this concept keq..here xor x = 83.33 = [p [r 100 83.33 = 16.67%

Q. At equilibrium [P] = 80% [R] = 20% Find out Keg 80 =4 k 20 Sol. Q. k 5, [P] = ? [R] = ? X Sol. 5 100-x 100-Xor x = 83.33 = [P [R 100 83.33 = 16.67%

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