Shweta thakur Asked a Question
October 16, 2020 2:44 pmpts 30 pts
Home Tools Puri Sharma Patha 384 704 4. Prefereatial Precipitation of an msoluble Salt. Silver chloride is insoluble or sparingly soluble, to be more accurate. So is silver iodide. The question. arises as to what would happen if potassium iodide solution is added to silver chloridc. Would the reaction KI KCI AgCI Sparingly soluble Agl Sparingly soluble take place towards the right, i.e., would the precipitate of silver chloride change into the precipitate of silver iodide ? For answer, it is necessary to ook to their respective solubility products. Solubility product of silver chloride Kp(AgC) [Ag ICI]= 1-56x10-10 (Table 7) and that of silver iodide, gpAgnAgI 0-94x1016 (Table 7) C 156x10 166 x 10 0.94 x 10-16-66 x 10 This means that at equilibrium, the concentration of Cl ions in solution is more than a million times greater than that of ions n other words, practically nothing of the 1onS can remain in solution at equilibrium. As the ions can only be removed as Agl, it means that the Feaction proceeds virtually to completion towards the right. As a rule, the compound with the lower solubility product gets precipitated in preference. Silver iodide has lower solubility product than silver chloride. Therefore, the former gets precipitated in preference to the latter 11.69 x8.26 in
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  • Suman Kumar
    Lower the Ksp less is the solubility
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    Suman Kumar
    AgI will be least soluble
  • Priyanshu kumar Best Answer
    Just for comparison... In general,the compound with lower solubility product gets precipitated first..Here AgI has lower Ksp than Agcl ..so it will precipitate first
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    Shweta thakur
    why sir??
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