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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Shweta Thakur posted an Question
November 04, 2020 • 02:45 am
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30 points
30 points
- IIT JAM
- Chemistry (CY)
Plz explain this heat oi tusion 1s 1769 ca mol [ans. 8-98 cal k mol- calculate the change in entropy when 40 g of water at
P VInE WII 1mOIe OI SOITa S0, meis at-76'T. The latent heat OI TuSion 1s 1769 ca mol [Ans. 8-98 cal K mol- Calculate the change in entropy when 40 g of water at 50°C are mixed with 80 g of water at -20°C. [Ans. 0-12 cal deg 5 iaulaa mal-1 J=l a1 For a certain ideal aas
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Priyanshu kumar Best Answer
check this
As here instead of 276.33 ,.276 is taken for easy calculation..so final answer differs...but check the process
sir
tf - 50 him chahite
heat gained = heat lost main Jo values put ke hai
dono likh sakti ho...magnitude same rahega...50-Tf or Tf-50
-90 aayega
aise
fr ye bhi change hoga na iske according...or -90 acceptable nhi na hoga...ye 50 or -20 ke beech ka hona chahiye
mtb
-20 se gain hoga or 50 se lost hoga...so -90 acceptable nhi hoga
but answer 0.12 hai
maine approx liya hai...see the solution...process me any doubt?
no sir
thanky
sir