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Priyanshu kumar Best Answer
Ketone oxidation implies the rupture of a C-C bond. If it is energic (KMnO4, K2Cr2O7) two carboxylic groups will be produced. If it is smooth (Baeyer-Villiger oxidation), an ester is produced that, once it is hydrolized, gives rise to a carboxylic acid and an alcohol.
Here in presence of energic and strong oxidising agent HNO3, two carboxylic acid is formed