Shweta Thakur posted an Question
January 18, 2021 • 02:57 am 30 points
  • IIT JAM
  • Chemistry (CY)

Plz explain this ques.... e heat of combustion of ethylene is 1411 kl, the

(a)-3-77 (b)-1-79 (cy-1005 (d) none of these 6. When a certain amount of ethylene was combusted, 6226 K) O If the heat of combustion of ethylene is 1411 kl, the volun entered into the reaction is a) 2965 mL (at NTP) that (c) 6226 x 22-4 litres (d) 224 litres (b) 296-5 litres

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    Priyanshu kumar Best Answer

    option B

    cropped7251780506245933786.jpg
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    how they have calculated moles of ethylene

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    dono value given hai

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    1411 heat of combustion hai or actually jo evolve hue h wo 6226 h

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    to moles 4.41 hue

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    sir 1411 kj 1 mole ke liye hai

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    haa isiliye na 6226 ....kitne moles ke liye honge wo find krna h

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    thanks

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