>
>
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Shweta Thakur posted an Question
February 18, 2021 • 04:26 am
![]()
30 points
30 points
- IIT JAM
- Chemistry (CY)
Plz explain this ques... the presence of cn, but do not react with strong acids such as h
PROBLEM 12 Explain why aldehydes and ketones react with a weak acid such as hydrogen cyanide in the presence of CN, but do not react with strong acids such as HCl or HSO4 in the pres ence of C or HSO PROBLEM 13 SOIVED
3 Answer(s)
Answer Now
- 0 Likes
- 5 Comments
- 0 Shares
-
Shweta thakur
sir plz tell me I thing that in intermediate which is strong base
-
![comment-profile-img]()
>
-
![comment-profile-img]()
>
Dinesh khalmaniya 1
explanation
![cropped5295480839784657550.jpg]()
-
![comment-profile-img]()
>
Priyanshu kumar Best Answer
Answer
![cropped1541245781031791096.jpg]()
![eduncle-logo-app]()
sir
![eduncle-logo-app]()
plz explain the intermediate state of this reaction
![eduncle-logo-app]()
...
![eduncle-logo-app]()
thk to hai and if strong acid rahenge to iske conjugate base weak honge then tetrahedral intermediate reh nhi payenge kyunki group easily eliminated ho jayenge and this doesn't happen in case of weaker acid
![eduncle-logo-app]()
shweta see yha pe cn- stronger conjugate base ho jayenge so eliminate nhi honge then tetrahedral intermediate bhi reh payenge and after that protonation occur and cyanohydrin form
![eduncle-logo-app]()
sir weaker acid ki jagah stronger acid aayega n iise pehle vale comment main
![eduncle-logo-app]()
sir. I want to know about o- usse Kuch fark ni pdega transition state ko ya cn ko
![eduncle-logo-app]()
no
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Suman Kumar![best-answer]()
In presence of HCl & H2SO4 enol & then again tautomerization led to the formation of ketone.
But in presence of HCN , NaCN act as catalyst. CN- initiative the reaction. And once the enolate is formed it abstract the proton from HCN