Plz explain this question ..i think the answer is b ... ves an absorption line of lowest frequency is a. n=1 to n=2 b. n-3 to n=8 c. n=2 to n=1

Do you remember that wave number formula? Apply that and calculate with both n values.. you'll get the answer. 😊

ok sir I have calculated

Absorption line in the spectra arise when energy is absorbed i.e., electron shifts from lower to higher orbit, out of a & b, b will have the lowest frequency as this falls in the Paschen series.

check this

sir

Okk😊

sorry i have taken 81 square of 9..correct there it is 64..But it is lowest

client error aa rha TB se

app ka problem rhta hai hmesha🙁

got this shweta??

I was saying for 1 to 2 energy gap is maximum n and for 3 to 8 gap is minimum right that's why for this frequency is more....because Freq. is directly related to energy

shweta for this type of ques...first of check for emissions and absorption case...then for absorption use this formula directly...you get it

here shweta absorption case..so we have to use this formula

shweta you think it correctly...3 to 8 energy gap.is.minimum then abvious frequency is minimum

Here ques asked for lowest frequency not for highest 😊

ok ok

but sir in my previous question why u have taken emmision case

mention to khin koya ni tha

there given shweta jumps and one thing...the colour of compound arises not by absorption but by emission

when the emitted light energy frequency falls in visible region

ok

sir thanku

always welcome shweta😊

check it

use this formula to calculate frequency

out of all options only A, and B give absorption spectrum while C,D give emition spectra

check this concept

you know E = -13.6/n2 so energy different of n8 to n3 will be lowest while maximum in n1 to n2. so Option B have lowest frequency

got it??

thanku so much sir