IIT JAM
Shweta thakur Asked a Question
July 24, 2020 1:18 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Plz explain this question... s of air at 25°c and 55 atm pressure, asc o-19%, n - 80% and co - 1% (by volume). calculato t 5-5 g of

-26-41 kcal/mole C+ 15-51-292. 12 Solution: Moles of C = = 1292. Moles of O, RT 0-0821 x 298 pV 5-5 x (0-19x 25) -1-068. CO C O xmoles X moles (say) C CO + (1-ction = number of moles of O after reaction moles of O in CO, + moles of O in CO 2x1-068 2x+ (1-292 x) or or X = 0-844 Mole of CO, = 0-844. Mole of CO = = 1292 0-844= 0-448. Total heat evolved = 0-844 (-94-05) +0-448 (-2641)
  • 1 Answer(s)
Answer Now
  • 0 Likes
  • 3 Comments
  • Shares
  • Priyanshu kumar thankyou
    check this short process of similar type
    • cropped5680329981428492225.jpg
    Likes(0) Reply(1)
    Priyanshu kumar
    check this
    • cropped1699432761429144671.jpg
  • Priyanshu kumar
    where you are facing problem shweta??
    Likes(0) Reply(3)
    Shweta thakur
    I didn't get the question sir
  • Suman Kumar
    Solution is provided. Where are you facing problem
    Likes(0) Reply(1)
    Shweta thakur
    I didn't get the question
How Eduncle Helps You ?
StudentTutorInstitutionApp
Help
FAQsPayment TermsRefund PolicyAsk Support
Head Office :
MPA 44, 2nd floor, Rangbari main Road Mahaveer Nagar II, Kota (Raj.) - 324005

Branch Office (Jaipur):
Shyam Tower, Plot No. F2, 6th Floor Amrapali Circle,
Vaishali Nagar, Jaipur, Rajasthan 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com