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Sourav posted an Question
September 13, 2020 • 17:08 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Plz solve this.

2 Answer(s) Answer Now
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    Ashutosh singh best-answer

    A option is correct.

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    After benzilic rearrangement, do nucleophilic substitution on Benzyl chloride, Sourav.

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    i m not able to do that from 2nd step.

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    from which oxygen should i act base and act phch2cl

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    Have a look, Sourav! 😊 Tell me Kahan pe doubt h!

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    i was asking why base didn't attack carboxylate ion and then carboxylate ion attack phch2cl2

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    Dear Sourav, even if takes H from carboxylate, it is not strong enough nucleophile to attack benzyl chloride.

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    it will remain in the form of O-Na+

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    EtO- will abstract both H, but the nucleophile associated with carboxylate is less nucleophilic than second one.

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    Hope you're getting what am trying to convey here, buddy.

  • Suman Kumar Best Answer

    option A is correct

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    yes how

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    Benzilic acid rearrangement you can do na

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    yes.. plz explain from 2nd step.. i formed up to benzilic.

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    Here EtO- is given in excess so both proton will be removed

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    yes.. after that im having trouble

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    But benzyl chloride is taken 1 equivalent so it attack oxide anion

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    As carboxylate anion is more stable

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    Sourav are you there

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    sir there should be sodium carboxylate na?

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    carboxylate anion will not attack

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    yes Sourav

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    im talking abt this.

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    yes Sourav you are right

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    only in one option there is both na and phch2cl used.. so i was having doubt.

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    it's okay.

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    understanding is more important

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