Shweta Thakur posted an Question
December 17, 2020 • 00:06 am 30 points
  • IIT JAM
  • Chemistry (CY)

Plz solve this... ... cid-base compare acidic strength of given compounds.

Acid-Base Compare acidic strength of given compounds.

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    Ashutosh singh best-answer

    See, here's an application of Bredt's rule, student. Double bond at bridge head is very very unstable. As soon has you deprotonate A, it can't delocalise it's negative charge on Oxygen through Mesomeric effect but, it will cost you making double bond at bridge head, which is highly unstable. B is more acidic, henceforth.

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    Dinesh khalmaniya 1 Best Answer

    2>1 1 is least stable because here after removing of acidic H+ negative charge formed is not resonating with C=O because here bridge head alkene is formed which is unstable according to bridts rule. while in case of 2, negative charge is delocalised with C=O

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    any doubt?

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    wait sir

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    yes

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    in second there is h u have not written

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    yes, what's your doubt

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    sir protonation krne pe hi we get minus sign n??

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    yes

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    sir second vale main bridgee to hai ni

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    bridge**

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    then how can we say ki vo double bond bridge pe ni hai

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    2nd wale me bridge nhi he to easily double bond exist krega

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