IIT JAM
Shweta thakur Asked a Question
June 7, 2020 10:24 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Plzexpalin that in first transition state here that why negative charge is on carbon although h is removing and why in second neg. charg. not appear

sec-Butyltrimethy lammoniunm ans hydroxide the developing double bond and shows little resemblanee with the final alkene. In contrast, the state for Saytzeff elimination is stabilized by the developing d
  • 3 Answer(s)
Answer Now
  • 0 Likes
  • 6 Comments
  • Shares
  • Shweta thakur
    they are
    • cropped8138697091132793724.jpg
    Likes(1) Reply(2)
    Suman Kumar
    Zaitsev product me alkene like transition state hai. That's why stable alkene is formed i.e more Substituted.
  • Suman Kumar thankyou
    Because in zaitsev transition state have alkene like transition state and that alkene is stable which has more no. of hyperconjugation.
    Likes(0) Reply(0)
  • Suman Kumar
    In zaitsev product more substituted alkene is formed. Why?
    Likes(0) Reply(1)
    Suman Kumar
    Did you get this
  • Dinesh khalmaniya
    hope this will help you 🙏
    Likes(0) Reply(0)
  • Dinesh khalmaniya thankyou
    it is E2 elimination reaction. base abstract the most acidic proton. so H gets partially positive charge whereas Carbon atom gets partially negative charge. Here H and leaving grou...
    Show more
    Likes(0) Reply(0)
  • Suman Kumar Best Answer
    In ist case notice that C-N bond is not broken till hydrogen is abstracted by base. So there is negative charge on carbon. But in 2nd case hydrogen is abstracted by base at the sam...
    Show more
    Likes(0) Reply(0)