Shweta thakur Asked a Question
June 7, 2020 10:24 pmpts 30 pts
sec-Butyltrimethy lammoniunm ans hydroxide the developing double bond and shows little resemblanee with the final alkene. In contrast, the state for Saytzeff elimination is stabilized by the developing d
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  • Shweta thakur
    they are
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    Suman Kumar
    Zaitsev product me alkene like transition state hai. That's why stable alkene is formed i.e more Substituted.
  • Suman Kumar thankyou
    Because in zaitsev transition state have alkene like transition state and that alkene is stable which has more no. of hyperconjugation.
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  • Suman Kumar
    In zaitsev product more substituted alkene is formed. Why?
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    Suman Kumar
    Did you get this
  • Dinesh khalmaniya
    hope this will help you 🙏
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  • Dinesh khalmaniya thankyou
    it is E2 elimination reaction. base abstract the most acidic proton. so H gets partially positive charge whereas Carbon atom gets partially negative charge. Here H and leaving grou...
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  • Suman Kumar Best Answer
    In ist case notice that C-N bond is not broken till hydrogen is abstracted by base. So there is negative charge on carbon. But in 2nd case hydrogen is abstracted by base at the sam...
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