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Shweta Thakur posted an Question

October 13, 2020 • 23:38 pm

30 points

IIT JAM
Chemistry (CY)

Plzexpalin this.... onded to forma square planar complex ion, [cu(ho)p and the 5th water molecule is hydroge

2 In the case of copper(11) sulphate, 4 water molecules are covalently bonded to forma square planar complex ion, [Cu(HO)P and the 5th water molecule is hydrogen bonded to this ion and a neighbouring sulphate on helping to hold the crystal lattice together. However, this blue crystal lattices readily broken down on heating, It is a reversible reaction, since, the white anhydrous solid turns blu on adding water (a simple test for water). CuSO, 5H,O(s) =CusO.(s) + 5H,O(g//) Blue White anhydrous solid Relative Acidity of Hydrated Salts

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Priyanshu kumar Best Answer

In CuSO4.5H2O,Cu is coordinated with 4 water molecules and two more oxygen atoms from Sulphate ion. Now fifth water molecule is hydrogen-bonded and is deeply embedded in a crystal. It is not coordinated. Only 4 water molecules are coordinated and the fifth is the only hydrogen bonded.
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4 water molecules covalently bonded hai jo square planar complex bna rhe hai...or 5th wale water molecules hydrogen bonded hai ion se or sulphate ion se
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when heated it is broken so form anhydrous white solid colourless or fr water add krne pe ye blue coloured ho jate hai
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In CuSO4.5H2O, water acts as ligand as a result it causes crystal field splitting. Hence d—d transition is possible in CuSO4.5H2O and shows colour. In the anhydrous CuSO4 due to the absence of water (ligand), crystal field splitting is not possible and hence no colour.
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Hope you got this ...and please ask if any doubt
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wait
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presence of water molecules se d d transition kaise hota can u explain it more
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ligand ke presence me hi na spliiting hote hai then after spliiting d-d transition occurs
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oh yes sir
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ye saare complex compound hain
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haa ye sab hydrated hai...water of crystallisation presence hai
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ok
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sir
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sir
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Dinesh khalmaniya 1

check it
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check it also
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ye mujhe samagh ni aata
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y
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kya smjh nhi aa rha
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ye d-d transition se related topic he
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neeche Jo structure bnaya vo konsa
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kyin ni hota d d transition
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vo jo apne bheja usi ka to explanation he.
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wait
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sir DD transition kyun ni possible hai in absence of watee
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aa gya samagh
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wait shweta I'm bit busy
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aa gya samagh koi aur doubt hota isme to I will ask
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okay
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sir Aapne Jo send kiya usme Likha ki octahedral arrangement is not present ....mujhe samagh ni aa rga khan ni present hai
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JB heating Hoti hai tb?
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?
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d-d transition vohi octahedral complex show krte he jisme centre of symmetry absent hoti he so 1st complex octahedral bhi he or centre of symmetry bhi absent he to p- d mixing hoti or colour show krega
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2nd complex octahedral nhi rhega because H2O molecule remove ho gye so p-d mixing nhi hogi or molecule become colourless
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ye structure Jo bnaya vo hydrated CUSO 4 Ka hai n anhydrous Ka ni n
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anhydrous ki geometry kaise hogi
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saare H20 no jayenge sir
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yes
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CuSO4 to ionic he
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yhan planar Likha aur aap octahedral keh re ho
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4 H2O molecule k sath square planar hi to hoga or mene CuSO4.5H2O ki baat ki he
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isko ache se pdo isme likha he 5th H2O molecule SO4 k sath H bonded he
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shi to likha he. bus language alg he
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CuSO4.5H2O ka coordination number 6 he so it is octahedral
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got it?
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yes sir
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sir it is an equilibrium reversible reqctio ?
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yes
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sir
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ye 4,7 water of crystallization kaise aate hai
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kon decide krte hain
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???smjh ni aya
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sir cuso4.5 H20 5 kaise hota ye
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is this an experiment result
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yes, ye apn decide nhi kr skte, complex isi form me exist krta he
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ok
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thanks sir🙏🙂
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Shweta Thakur posted an Question

Plzexpalin this.... onded to forma square planar complex ion, [cu(ho)p and the 5th water molecule is hydroge

Priyanshu kumar Best Answer

Dinesh khalmaniya 1

Eduncle

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IIT JAM

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Top Resources

Shweta Thakur posted an Question

Plzexpalin this.... onded to forma square planar complex ion, [cu(ho)p and the 5th water molecule is hydroge

Priyanshu kumar Best Answer

Dinesh khalmaniya 1

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