Himanshu posted an Question
May 01, 2020 • 07:22 am 30 points
  • IIT JAM
  • Physics (PH)

Previous year

what should be it's answer ????according to me it should be 1,2&4

2 Answer(s) Answer Now
  • 0 Likes
  • 4 Comments
  • 0 Shares
  • comment-profile-img>
    Ruby negi

    1. option 1st is correct as u discussed a lot in one previous question of urs.. so statement 1is correct .. 2. for reversible cyclic process, close integration of dQ/T=0 so dQ=0 while close integration of dQ/T<0 in irreversible case so dQ<0 therefore statement 2 is correct.. 3 and 4statement also correct as more heat converted into work and vice versa in case of reversible cyclic process

    cropped-1773368451.jpg
  • comment-profile-img>
    Abhishek singh

    As far as I understood the question. Options 1, 3, 4 should be correct. Do let me know, if it is so? Then only I would share my thoughts. Best regards.

  • comment-profile-img>
    Dhairya sharma Best Answer

    As you know entropy in reversible process is constant so change in entropy would be zero.so 1 is correct.  In an ideal thermodynamically reversible process, the energy from work performed by or on the system would be maximized, and that from heat would be zero. so 2 is also correct. and also we know more heat is converted into work in reversible process due to no loss.so 3 is also correct.

whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers