Raghav posted an Question
April 08, 2022 • 22:19 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Proce that lim{(1+1/n^2)(1+2/n^2)(1+3/n^2)}^(n^2) = e^6

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  • Anonymous User best-answer

    since limit (1+a/n)^n=e^a therefore lim{(1+1/n²2)(1+2/n²2)(1+3/n²2)}^n² lim(1+1/n^2)^n².(1+2/n²)^n².(1+3/n²)^n² lim(1+1/n^2)^n².limit(1+2/n²)^n². limit(1+3/n²)^n² e¹.e².e³=e¹+²+³=e⁶

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