Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Imdadul Haque posted an Question
December 19, 2020 • 15:14 pm
![]()
30 points
30 points
- IIT JAM
- Chemistry (CY)
Produced. when 2.063 grams ofa hydrocarbon, ch, were burned in a combustion analysis apparatus, 6.320 grams of co2 and 3.019 grams of h20 were in a separate exp
produced. When 2.063 grams ofa hydrocarbon, CH, were burned in a combustion analysis apparatus, 6.320 grams of CO2 and 3.019 grams of H20 were In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
1 Answer(s)
Answer Now
- 0 Likes
- 2 Comments
- 0 Shares
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Suman Kumar Best Answer
Molecular formula : C6H14 Empirical formula :. C3H7 This is the reaction : 2C6H14 + 19O2 → 12CO2 + 14H2O
Sir please ,, paper work rough v chlega .. method samajna haii
ok
see