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Divya posted an Question
September 05, 2020 • 00:40 am 30 points
  • IIT JAM
  • Chemistry (CY)

Product formation

sir can you explain how this NaNH2 reacts with the bulky molecule

2 Answer(s) Answer Now
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    Priyanshu kumar best-answer

    Nanh2 is strong base..so it will deprotonates

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    First benzoic acid deprotonates by nanh2 and then phenolic part on the left

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    Priyanshu kumar Best Answer

    see

    cropped7392263359089579460.jpg
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    First check acidity and then 2 moles Nanh2 is there...one by one deprotonation takes place

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    got this Divya??

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    https://www.masterorganicchemistry.com/2011/07/29/reagent-friday-sodium-amide-nanh2-2/ check for sodium amide reagent

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    sorry for late response sir

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    it's okay😊

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    sir because of NO2 left side OH is more a acidic right

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    yes 😊👍

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    yes sir got it

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    today I have learned many key points

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    thank you so much for helping me sir

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    we're always with you for your help

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