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Harsh Saxena Asked a Question
August 22, 2020 2:55 pmpts 30 pts
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  • Anonymous User Best Answer
    For any Bn =( b1,b2,......) , there exists An = (0,b1,b2,....) such that T(An) = Bn.... therefore T is onto
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  • Anonymous User
    Take An = (1,0,0,.....) and Cn = (2,0,0,...). Then, T (An) = T (Cn) =(0,0,0,...) but An is not equal to Cn. Hence, T is not one one
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