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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Priyanshu kumar Best Answer
for 21 and 22 option A is correct
sir explain question 22
Dear shib fac and mer isomers are only shown by M(A-B)3 type complex...only 1st option fulfill this criteria
got shib??
please respond dear shib
but sir i read that if three ligands are on 90°angle then fac and 1is 90°and 2 is 180° then meridonial will form but incase of m(ab)3 there is only two atoms with chains
check the position of O atom and N atom
Easily you can explain in MA3B3 type complex....but in case of chelating ligand check the position of atoms in ligands...for checking fac and mer isomers
then sir tell me how can i solve chelating ligand complex
In this you check na position of atom which you consider the position in fac n mer isomers as like MA3B3 complex