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Shelly Asked a Question
May 31, 2020 5:37 pmpts 2 pts
  • IIT JAM
  • Mathematics (MA)

Q.1 (msq) the solutions of the differential equation -(sin 2r)y; u(0)-0 (a) v(r) =0 (c) u{z) = (#) sin"z (b) u(r)= - ()sinz (d) ur)- ()cos 1/2 1/2

Q.1 (MSQ) The solutions of the differential equation -(sin 2r)y; u(0)-0 (a) v(r) =0 (c) u{z) = (#) sin"z (b) u(r)= - ()sinz (d) ur)- ()cos 1/2 1/2
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  • Deepak singh 1 thankyou
    option a and c are correct. see attached solution for detail.
    • cropped1084151072.jpg
    Likes(1) Reply(2)
    Deepak singh 1
    if any doubt please ask
  • Dhairya sharma
    see attached it will help you.
    • cropped400921625449259578.jpg
    Likes(1) Reply(1)
    Dhairya sharma
    see attached
  • Bhedesh kumar
    a,b,c
    Likes(0) Reply(0)
  • Ujjawal vishal
    options a and c both satisfy given IVP
    Likes(0) Reply(0)
  • Ruby negi
    i used cos2x=1-2*(sinx)^2.... this is simple question, do urself too ..
    Likes(1) Reply(0)
  • Ruby negi thankyou
    solution...
    • cropped1915453201.jpg
    • cropped1737842925.jpg
    Likes(1) Reply(0)
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