Shelly posted an Question
May 31, 2020 • 23:07 pm 2 points
  • IIT JAM
  • Mathematics (MA)

Q.1 (msq) the solutions of the differential equation -(sin 2r)y; u(0)-0 (a) v(r) =0 (c) u{z) = (#) sin"z (b) u(r)= - ()sinz (d) ur)- ()cos 1/2 1/2

Q.1 (MSQ) The solutions of the differential equation -(sin 2r)y; u(0)-0 (a) v(r) =0 (c) u{z) = (#) sin"z (b) u(r)= - ()sinz (d) ur)- ()cos 1/2 1/2

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    Ruby negi

    i used cos2x=1-2*(sinx)^2.... this is simple question, do urself too ..

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