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August 26, 2020 3:23 pm 30 pts
Q.12 Consider a uniform thin circular disk of radius R and mass M.A Concentric square or Side is Cur ne disk (see figure). What is the moment of inertia of the re eSde R2 Is cut esuitant dtsK about an axIS passing through the centre of the disk and perpendicular to it? ()I- - (8) I|- () I-|
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• Chandra dhawan
Moment of inertia of the circular disc about a line perpendicular to the circular disc through it's center=MR^2/2 .now if we cut out a square lamina of side R/2 then moment of iner...
• Chandra dhawan
Chandra dhawan
see
• Chandra dhawan
Moment of inertia of the circular disc about a line perpendicular to the circular disc through it's center=MR^2/2 .now if we cut out a square lamina of side R/2 then moment of iner...
Chandra dhawan
hope you get it
see attached
Vaishnavi rajora
for query, please drop a comment
• Ruby negi
first, find the moment of Inertia of disc(assuming that no square is cut out from disc) then find the moment of inertia of square and subtract the two. u will get ur result...