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Isha lohan Asked a Question
August 26, 2020 3:23 pmpts 30 pts
Q.12 Consider a uniform thin circular disk of radius R and mass M.A Concentric square or Side is Cur ne disk (see figure). What is the moment of inertia of the re eSde R2 Is cut esuitant dtsK about an axIS passing through the centre of the disk and perpendicular to it? ()I- - (8) I|- () I-|
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  • Vaishnavi rajora Best Answer
    see attached
    • cropped4794306091687553867.jpg
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    Vaishnavi rajora
    for query, please drop a comment
  • Chandra dhawan thankyou
    Moment of inertia of the circular disc about a line perpendicular to the circular disc through it's center=MR^2/2 .now if we cut out a square lamina of side R/2 then moment of iner...
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    Chandra dhawan
    hope you get it
  • Ruby negi
    seee....
    • cropped1797252215.jpg
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    Ruby negi
    for Doubt u can ask...
  • Chandra dhawan
    see also
    • cropped1636691674281109885.jpg
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    Chandra dhawan
    see
  • Ruby negi
    first, find the moment of Inertia of disc(assuming that no square is cut out from disc) then find the moment of inertia of square and subtract the two. u will get ur result...
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  • Chandra dhawan
    Moment of inertia of the circular disc about a line perpendicular to the circular disc through it's center=MR^2/2 .now if we cut out a square lamina of side R/2 then moment of iner...
    Show more
    Likes(0) Reply(0)