profile-img
Isha lohan Asked a Question
August 22, 2020 11:51 ampts 30 pts
Q.39 Consider a classical particle subjected to an attractive inverse-square force field. The total energy of the particle is E and the eccentricity is E. The particle will follow a parabolic orbit if (A) E>0 and e = 1 (C) E = 0 and e = 1 (B) E <0 and e < 1 (D) E S0 and e =1
  • 2 Answer(s)
  • 0 Likes
  • 3 Comments
  • Shares
  • Ruby negi Best Answer
    see this too..
    • cropped-911287062.jpg
    Likes(0) Reply(0)
  • Ruby negi thankyou
    eccentricity is zero for circle, between zero to one for ellipse, one for parabola and above 1 for hyperbola..
    Likes(1) Reply(1)
    Isha lohan
    I understand eccentricity. But how to get energy value.
  • Ruby negi
    energy zero, eccentricity 1.. option c
    Likes(1) Reply(1)
    Isha lohan
    how to say Energy is zero?
Head Office :
MPA 44, 2nd floor, Rangbari main Road Mahaveer Nagar II, Kota (Raj.) - 324005

Branch Office (Jaipur):
Shyam Tower, Plot No. F2, 6th Floor Amrapali Circle,
Vaishali Nagar, Jaipur, Rajasthan 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com