Isha lohan Asked a Question
August 22, 2020 11:51 ampts 30 pts
Q.39 Consider a classical particle subjected to an attractive inverse-square force field. The total energy of the particle is E and the eccentricity is E. The particle will follow a parabolic orbit if (A) E>0 and e = 1 (C) E = 0 and e = 1 (B) E <0 and e < 1 (D) E S0 and e =1
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  • Ruby negi Best Answer
    see this too..
    • cropped-911287062.jpg
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  • Ruby negi thankyou
    eccentricity is zero for circle, between zero to one for ellipse, one for parabola and above 1 for hyperbola..
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    Isha lohan
    I understand eccentricity. But how to get energy value.
  • Ruby negi
    energy zero, eccentricity 1.. option c
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    Isha lohan
    how to say Energy is zero?