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Isha Lohan posted an Question
September 05, 2020 • 15:13 pm
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30 points
30 points
- IIT JAM
- Physics (PH)
Q.42 a particle of unit mass is moving in a one-dimensional potential v(x) = x*-x*. the minimum mechanical energy (in the same units as (x)) above which the mot
Q.42 A particle of unit mass is moving in a one-dimensional potential V(x) = x*-x*. The minimum mechanical energy (in the same units as (x)) above which the motion of the particle cannot be bounded for any given initial condition is: (Specify your answer to two digits after the decimal point.)
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Mahak
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see attached ans is 0.25 units
![cropped3559214301019617376.jpg]()
![cropped4958296697141279640.jpg]()
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please explain how you calculated Emin?
![eduncle-logo-app]()
at the last few steps?
![eduncle-logo-app]()
see double derivative is max at x= 1/root 2
![eduncle-logo-app]()
so for E min double derivative must be lest than zero
![eduncle-logo-app]()
so it is less than zero at x=1/root 2
![eduncle-logo-app]()
put x=1/root 2 in V and E min will come
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Chandra prakash Best Answer
see attachment...dear
energy is equivalent to potential energy...so given potential we put value of x and solve it