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Deepak Patra posted an Question
December 04, 2021 • 15:35 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Q.no. 25 let u(x, t) be the solution of 0u 3u = 0, u(x,0) = f(x), arx,0)= 0, x e r,t >0, at2 0x2 where f is a twice continuously differentiable function. if f(-

Q.No. 25 Let u(x, t) be the solution of 0u 3u = 0, u(x,0) = f(x), arx,0)= 0, x E R,t >0, at2 0x2 where f is a twice continuously differentiable function. If f(-2) = 4.f(0) = 0, and u(2,2) = 8, then the value of u(1,3) is _

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