Sayan Asked a Question
June 6, 2020 9:48 pmpts 30 pts
Q4. In the arrangement shown, the system is released freF rest and all surfaces are frictionless. Then the value 'm' for which the 2 kg block remains stationary relal to the wedge is / 2 kg 3 kg 30 m 5 (1) 5 v3-1 kg 3+1) k9 (3) 5(3+1) kg Spring force (4) 10(/3-1) kg
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  • Ruby negi thankyou
    for any doubt u can ask...
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    madam i didn't understand still properly.madam provide the mathematical calculation also..
  • Ruby negi Best Answer
    I drew the free body diagram of all the masses... using these diagram, write the equation of motions, note that 2kg mass is to be at rest so the resultant on 2kg is zero...
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