Sudarshan posted an Question
April 21, 2020 • 01:00 am 30 points
  • IIT JAM
  • Physics (PH)

Q72. a body executes simple harmonic motion about the origin with amplitude a = 13 cm and period t = 12 sec. at time t = 0 it is at x = 13 cm. the shortest time

Q72. A body executes simple harmonic motion about the origin with amplitude A = 13 cm and period T = 12 sec. At time t = 0 it is at x = 13 cm. The shortest time of passage from x= 6.5 cm to x = -6.5 cm is (a) 4 sec (b) 3 sec (c) 2 sec (d) 1 sec

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    Abhishek singh best-answer

    Option C is correct. A detailed solution is attached. Enjoy the physics behind it. Best regards.

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    Ruby negi Best Answer

    equation of simple harmonic can be Asinwt or Acoswt but according to the given conditions in the question, u have to take Acoswt .. solution may help u . for any doubt please ask.

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    Shanu arora best-answer

    here is the solution , ans is 2 sec , here I have used the cosine form , one can also use the sine form but an extra π/2 have to carry in calculation . wo better choose the one where delta becomes zero before one begins with calculations . free feel to ask doubts .

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