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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
Que no 14 and 15
que no 14 and 15,.........................................
2 Answer(s)
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Priyanshu kumar Best Answer
The average distance and the most probable distance of an electron from the nucleus in the 1s orbital of a hydrogen atom are equal to 1.5a0 and a0 (Most probable distance is the distance where electron is highest probable so it is the radius of that orbit a0). The value of 1.5a0 is 0.529A˚. Hence, the average distance and the most probable distance of an electron from the nucleus in the 1s orbital of a hydrogen atom are equal to 0.794A˚ and 0.529A˚ respectively.
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Dinesh khalmaniya 1![best-answer]()
15) option D
sir they have given lymen series and it s wavelength na
it's given only to confused students
can we solve by this
?
1 baar try krke dekho
nhi aa raha isse😞
wait
lymen series k liye ye formula use nhi kr skte
yes wala formula use me ata he pr isse mass nhi niklega to hm direct calculate krege
ohkk