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Vivek posted an Question
July 09, 2020 • 14:51 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Question 19 2-0.66 the solutions of the diff eqn y +ay +by =0 ,where a and the constant.choose the correct cannot be bounded and periodic both can be bounded on

Question 19 2-0.66 The solutions of the diff eqn y +ay +by =0 ,where a and the constant.choose the correct cannot be bounded and periodic both Can be bounded on a uncountable set can ne unbound on a uncountable set can never be a periodic function with fundamental period

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  • comment-profile-img>
    Deepak singh 1

    according to me , option 2 and 3 are correct , see attached above .

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    Piyush pachauri Best Answer

    In my opinion option(ii) is correct. Option (iii) depends on the set.

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    sir option 4bhi sahi diye huye hai

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    option (iv) to true nahi hoga ,agar question sahi h to

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    agar b positive and a=0 rakh do, to sinax type ka solution mil jayega

  • comment-profile-img>
    Piyush pachauri best-answer

    PFA. If you take a bounded uncountable set then every solutions should be bounded. Please correct me if I'm missing something.

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    e^(ax) or e^(-ax) is not bounded, see graph

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    they will be bounded if x Belongs to (0,1) as this is also a uncountable set.

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    Yes vivek, What is your doubt?

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    in question there is not mention that x belongs to (0,1)

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    it can be any uncountable set

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    in question it is unbounded ,it is not mentioned either.

  • comment-profile-img>
    Deepak singh 1

    solution will be of type Ae^(-yx) where A belongs to R , and is not bounded ( see graph ) in attached

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