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Isha Lohan posted an Question
September 01, 2020 • 16:04 pm 30 points
  • IIT JAM
  • Physics (PH)

Question: 26/60 a particle free to move along the x-axis has potential energy given by u(x) =k[1 exp (-x)]for o xsto, where k is a positive constant of appropri

Question: 26/60 A particle free to move along the x-axis has potential energy given by U(x) =k[1 exp (-x)]for o xSto, where k is a positive constant of appropriate dimensions. Then At points away from the origin, the particle is in unstable equilibrum For any finite non-zero value of x, there is a force directed away from the origin (A) (B) (C) f its total mechanical energy is k2, it has its minimum kinetic energy at the orign For small displacement from x = 0, the motion is simple harmonic (D)

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  • Samveel ansari

    if other options are wrong,plz disprove it also??

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    Chandra prakash best-answer

    option d is correct... as x=0 is stable equilibrium position so motion about x=0 after some small displacement is simple harmonic...

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    how do we know that C option is wrong?

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    Ruby negi Best Answer

    option d is correct... as x=0 is stable equilibrium position so motion about x=0 after some small displacement is simple harmonic... motion about stable equilibrium is oscillating..

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    what can we say about option C?

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