Anukruti posted an Question
January 03, 2021 • 19:20 pm 30 points
  • IIT JAM
  • Geology (GG)

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    Rahul kumar Best Answer

    Answer: 95.6% Total volume of spherical rock = 4/3 × pi × (r)^3 = 4/3 × 3.14 × (5 cm)^3 = 523.33 cm3 Total occupied volume = Volume of sand = 23 cm3 Total volume of pores = Total volume of spherical rock - Total occupied volume = 523.33 - 23 = 500.33 cm3 Pore percentage = (Volume of pores / Total volume) × 100 = (500.33 / 523.33) × 100 = 95.6%

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