Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Rahul kumar Best Answer
Answer: 95.6% Total volume of spherical rock = 4/3 × pi × (r)^3 = 4/3 × 3.14 × (5 cm)^3 = 523.33 cm3 Total occupied volume = Volume of sand = 23 cm3 Total volume of pores = Total volume of spherical rock - Total occupied volume = 523.33 - 23 = 500.33 cm3 Pore percentage = (Volume of pores / Total volume) × 100 = (500.33 / 523.33) × 100 = 95.6%