Keerthi posted an Question
October 16, 2020 • 13:27 pm 30 points
  • IIT JAM
  • Chemistry (CY)

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  • Narayanarao gundoju

    7 pi bonds are present in given molecule accordingly Huckel's rule it is obeys (4n+2)e- rule hence n = 3 aromatic compound one π-bond is not involved in delocalization. thank you

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    Dinesh khalmaniya 1

    here n=3. It shows peripheral resonance so peripheral double bonds count for aromaticity. here peripheral double bonds are 7 so 4n+2 = 14 => 4n= 12 => n=3

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    Priyanshu kumar Best Answer

    n=3.. 14 pi electrons... 4n+2=14 ,n=3

    cropped1726522399058660547.jpg
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    peripheral aromaticity

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    sir what s peripheral aromaticity

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    we count the pi electron of only peripheral part...middle pi electrons not count for aromaticity

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    https://youtu.be/4G51MOznJnU watch this video

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    okk sir thank you

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    keerthi see all other answer and please ask if any doubt comes

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