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Imdadul Haque posted an Question
December 02, 2020 • 03:34 am 30 points
  • IIT JAM
  • Chemistry (CY)

(r)-2-methyl-1-butanol has a specific rotation of +13.5. the specific rotation of 2-methyl-1- butanol containing 40% of the (s)-enantiomer is o (round off to on

(R)-2-methyl-1-butanol has a specific rotation of +13.5. The specific rotation of 2-methyl-1- butanol containing 40% of the (S)-enantiomer is o (Round off to one decimal place) The number of gauche-butane interaction(s) in the following compoundis CH, CH

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    Ashutosh singh best-answer

    S is 40% in the mixture. Therefore, R will be 60%. Enantiomeric excess will be 20. Now, ee = specific rotation of mixture X 100/ specific rotation of pure enantiomer 20 = (x) X 100 / 13.5 Find x.

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