(R)-2-methyl-1-butanol has a specific rotation of +13.5. The specific rotation of 2-methyl-1- butanol containing 40% of the (S)-enantiomer is o (Round off to one decimal place) The number of gauche-butane interaction(s) in the following compoundis CH, CH
S is 40% in the mixture.
Therefore, R will be 60%.
Enantiomeric excess will be 20.
Now,
ee = specific rotation of mixture X 100/ specific rotation of pure enantiomer
20 = (x) X 1...