Relationship in between ch3 ch3 h c hc ci ci and ci h h ch (b) meso. (c) enantiomer. (d) structural isomer. (a) diastereomer.

got it??

sir can you explain please

Both structures are not eclipsed. Make them eclipsed first.

They can rotate about C-C single bond. You will see that all the identical groups will be eclipsed.

If you'll convert that eclipsed structure into Fischer projection, You'll find a plane of symmetry.

Did you get it?

sir fischer me agr R S configuration se check kese kre

Wo bhot time consuming ho jayega Reshav. Fir bhi main bta deta hun...dekho meso compound me kya hota h...Do identical optical active centres hote hain.. identical matlab identical environment..tum distinguish nahi kar sakte!! Us case me ek centre 'R' hoga toh dusra definitely 'S' hoga!

Toh agar R wala centre clockwise ghumayega PPL ko..toh S wala similar amount me anti-clockwise ghuma dega...overall optical rotation '0' ho jayega! that's why meso compounds are optically inactive.

Meso compounds are optically inactive due to internal compensation.

sir first wale me newman se check kre to cos bhi present hogi na

Jab ek chij dikh gyi apne ko, toh dusre pe kyun matha marenge? ya toh POS dikh jaye...ya toh COS! either of them will make our molecule optically inactive. 😀

yes sir me bhi try krta hu ki ese newman me hi question ho jaye fischer me convert na krna pde because boht time lg jata hai phir

Dekho Reshav, ek trick sun lun...agar Newman me jo eclipsing structure hote hain..agar usme har ek group ke peeche same group h..toh wo meso h..usme kuch dekhne ki zarurat nahi h!