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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Priyanshu kumar Best Answer
Second is more stable than 1st divya
the boron octet is complete in 2nd one
This is formal charges given not real charges
got Divya??
In 2nd figure also ...positive charge is on more eletronegative fluorine atom..makes it unstable
and charge separation also in 2nd
so equally stable...but octet preference you give here ...as there is formal charge not real charge in 2nd one
hope you got this
sir where is nitrogen atom here
sorry fluorine π
any doubt divya you can ask me
sir the positive charge on F generally makes unstable but as you said this is formal charge because of octet 2nd is stable.Am I correct
yes divya
and octet of boron is also complete
Yes sir I got it
ππ