Eakvira posted an Question
July 13, 2020 • 14:37 pm 30 points
  • IIT JAM
  • Physics (PH)

Rom () soved examples on method i e1 solve xdy ydx+ 2xdx = 0. nis equation is not exact as it does not satisfy the condition of exact equation. 2020.0%13-09.03

I dont understand this example ,how integrating factor is come in this

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    Ravi prakash yadav best-answer

    for exact differential for eqn Mdx+Ndy=0,the condition is dM/dy=dN/dx(d here is partial differentiation) For integration factor for equation of the type dy/dx+Py=Q(x), IF=exp(integration of P(x)dx) see the attachment for better understanding

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    cropped3862903408318203663.jpg
  • comment-profile-img>
    Ruby negi

    it doesn't satisfy exact differential condition so I did it with partial differential method...

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