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Imdadul Haque posted an Question
October 13, 2020 • 14:37 pm 30 points
  • IIT JAM
  • Chemistry (CY)

S0. amange the following compound in order of increasing bosicity. () ch il) h,c- h,c (iv) ch (a) i> ii> ii > iv (c)1> ii > v> ii| (b) i> m> ii> v (d) v> il> i>

s0. Amange the following compound in order of increasing bosicity. () CH Il) H,C- H,C (IV) CH (a) I> II> II > IV (c)1> II > V> II| (b) I> m> II> V (d) V> Il> I> II

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    Priyanshu kumar best-answer

    Option A is correct basicity order 1>2>3>4

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    pyridine is least basic here , 2,6 dimethylpyridine is most basic then 2 methyl pyridine, then 2-tertbutylpyridine....

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    why Sir ??

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    yes explaining

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    Okay sir

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    Ch3 group releases electrons due to inductive effect and hyperconjugation effect whereas tertbutyl group releases electrons only due to inductive effect...so 1 and 2 is more basic than 3rd...while in 1st there is 2 ch3 group so most basic

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    and methyl group mesomeric effect show nhi krte hai

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    okay sir thank you

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    check previous question too dear

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    Imdadul haque

    Sir Explanation

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    Ans pata nehii Sir .

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    okay sir 👍😊

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    Sir Ortho effect Aniline & benzoic acid Mai lgta haii Aisha pdha tha ,,,Kya ow pyridene pe v lag skta haii ??

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    sorry sorry wait

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    check it

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    actually mere mind me pyridine ki jgh aniline hi imagine ho rha tha because verbally solve krne ki kosis kr rha tha sorry for that..

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    and thank you for correcting me👍

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    now got it??

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    Sir Methyl group +M effect dekhata haii Kya ??

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    Dinesh khalmaniya 1 Best Answer

    option D IV is most basic because there is no ortho effect

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    sorry Option A is correct..

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