Nutan Kumari posted an Question
January 05, 2020 • 16:03 pm 15 points
  • IIT JAM
  • Physics (PH)

SECTION-(A) MULTIPLE CHOICE QUED ind the work done by a force F = = (y? cos x + z3) i + (2y sin x - 4) j + (3X z< + 2)k in movinn a particle from P(O, 1, -1) to

SECTION-(A) MULTIPLE CHOICE QUED ind the work done by a force F = = (y? cos x + z3) i + (2y sin x - 4) j + (3X z< + 2)k in movinn a particle from P(O, 1, -1) to Q-12 (A) 5T (B) (D) 15 47 57 + 15 9+ 97 (C)

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  • Dr. manish kumar gupta

    You should try in this way: let's take the origin 'O' at (0,0,0). Position vector of point 'P' will be: OP = 0i + 1j + 1k Similarly, position vector of OQ is: OQ = (π/2) i - 1 j + 2 k so displacement of the particle is: dx = PQ = OQ - OP = (π/2) i - 2 j + 1 k now work done should be dw = f.dx Solve it, you should get the answer.

  • Dr. manish kumar gupta

    You should try in this way: let's take the origin 'O' at (0,0,0). Position vector of point 'P' will be: OP = 0i + 1j + 1k Similarly, position vector of OQ is: OQ = (π/2) i - 1 j + 2 k so displacement of the particle is: dx = PQ = OQ - OP = (π/2) i - 2 j + 1 k now work done should be dw = f.dx Solve it, you should get the answer.

  • Dr. manish kumar gupta

    You should try in this way: let's take the origin 'O' at (0,0,0). Position vector of point 'P' will be: OP = 0i + 1j + 1k Similarly, position vector of OQ is: OQ = (π/2) i - 1 j + 2 k so displacement of the particle is: dx = PQ = OQ - OP = (π/2) i - 2 j + 1 k now work done should be dw = f.dx Solve it, you should get the answer.

  • Dr. manish kumar gupta best-answer

    You should try in this way: let's take the origin 'O' at (0,0,0). Position vector of point 'P' will be: OP = 0i + 1j + 1k Similarly, position vector of OQ is: OQ = (π/2) i - 1 j + 2 k so displacement of the particle is: dx = PQ = OQ - OP = (π/2) i - 2 j + 1 k now work done should be dw = f.dx Solve it, you should get the answer.

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