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Sourav posted an Question
August 15, 2020 • 06:31 am 30 points
  • IIT JAM
  • Chemistry (CY)

Select the incorrect statement about the product mixture in the following reaction: b products ccl4 64. (b) it is racemic mixture (d) it is a mixture of erythro

Select the incorrect statement about the product mixture in the following reaction: B Products CCl4 64. (b) it is racemic mixture (d) it is a mixture of erythro compounds (a) it is optically active (c) it is a resolvable mixture In the aiven reaction:

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    Ashutosh singh

    Let me explain this to you in a very lucid way, my Friend! See, this molecule is optically inactive due to internal compensation which is nothing but two chiral centres within a molecule with opposite and equal rotations.

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    Racemic mixture is always optically inactive!

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    sir i guess this molecule is optically inactive due to external compensation not internal.

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    Yes, Sourav. 😊 External compensation...you are right, absolutely. 😊

  • Amol ashok pawar Best Answer

    Option a

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    i couldn't understand

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    First of all it is erythro which is correct. second it is resolvable as different alkyl gr attached so option c is also correct as for option b it's racemic which means both dl pairs are possible so option b is also correct.

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    for option a it is optically active which is incorrect as a racemate is optically inactive hence option a is incorrect

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    but in the diagram it is saying the compound is optically active?

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    yes because it states the incorrect statement

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    are optically inactive molecule resolvable?

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    yes

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    so optically active compound are not resolvable?

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    they both are resolvable but racemic mixtures dl pair have a plane of symmetry which makes them optically inactive

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    how to know if a molecule is resolvable or not?

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    There’s no way to know, a priori, whether any of the common resolution methods (crystallization, chiral derivatizing agents, or chiral column chromatography) will work on a particular racemic mixture. hope this helps

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    the product have two chiral centre so it is definitely resolvable

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