Debarshi banerjee Asked a Question
September 9, 2020 12:12 ampts 10 pts
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  • Jagat Chaudhary thankyou
    check this image attached for solution
    • cropped1132253578164724086.jpg
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  • Srinath
    Replace the cos(π/(2^k)) terms by [sin(2*(π/(2^k))]/2sin(π/(2^k)). You can evaluate the limit then. If you have doubts, tell me.
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