Ashwini posted an Question
June 19, 2020 • 03:36 am 30 points
  • IIT JAM
  • Mathematics (MA)

Sin (n!r) then iff x)= lim lim n 0 sin (n!tx) +1 (a) f (x) is nowhere continuous (b) f a) has only 2 point of discontinuity (c)f) has only 2 point of continuity

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  • Pulkit khandelwal best-answer

    t tends to zero but not zero. but when sin(n!pix)=0 numerator zero but denominator not. when x is rational n!x is integer as n tends to infinite and sin term become zero so f(x) is zero when x is irrational we put limit of t and f(x) become constant so f(x)=0 ;x is rational f(x)=1;x is irrational function nowhere continuous

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