Shweta Thakur posted an Question
July 02, 2020 • 20:35 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Sir plz check this ....just want to ask that is it follows e2 mecganism ?? hc. koh sten bac m br oh- - c-h h c-c b

Hc. KoH STen bac M Br OH- - C-H H C-C Bplz explqin gjgjk

3 Answer(s) Answer Now
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  • comment-profile-img>
    Dinesh khalmaniya 1 Best Answer

    yes, you are absolutely correct 👍👍

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    sir if br is on second carbon then we have first rearrange then attack of oh plz see the picture I have marked second position of carbon

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    no, here rearrangement is not possible because it is biomolecular elimination. so H and Br will be removed simultaneously

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    here most substituted alkene is formed as a major product. see another image sent by me

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    sir if br is present on second carbon then also we donot have to rearrange

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    yes

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    ok sir thanks

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    Priyanshu kumar best-answer

    got shweta??

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    yes sir

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    just tell me if br is present on second carbon( I have marked there) then also E2**** follows with rearrangement **

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    see for this elimination is alpha beta elimination

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    so rearrangemt is not possible

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    but sir tertiary halide is more stable than secondary

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    so elimination occurs from alpha beta position

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    wait I send u

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    whenever there is formation of carbocation then always check for arrangement otherwise not

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    sir see

  • comment-profile-img>
    Priyanshu kumar

    see mechanism...no intermediate rather transition state is formed

    cropped1303688306639063409.jpg
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    I have also made tran.state

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    yes it is true

  • comment-profile-img>
    Priyanshu kumar

    yes you did it right as strong base is there and one step reaction us there

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    if you get it then please give your feedback too shweta

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