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sir solve it useing cauchy 1st theorem ????
not solve by cauchy theorms
response every question with best answer
you take un √n/(√3n+√3n+3) if u put n=1 you not get u1
sir putting n= 1 ,2 ,3 .... corresponding u1, u2, u3.... are getting ... sir .????
n=1 u1= √1/√3+√6 ; n=2 u2=√2/(√6+√9)