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Sourav posted an Question

October 07, 2020 • 02:29 am

30 points

IIT JAM
Chemistry (CY)

Solve this qs

2 Answer(s)

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Dinesh khalmaniya 1

option A. II show SIR effect. due to SIR there is no resonance possible in II. so less dipole moment is shown by II
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how dipole is formed
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in fig 1 there is resonance so the NO2 is planar in the plane of benzene ring so the dipole moment is high (it cant cancel the dipole moment of CH3 grops attached to other nitrogen as it is in other plane , in other words it hasnt got a cancelling component of dipole moment in the other plane ) in fig 2 however the bulky CH3 groups force NO2 out of the plane of benzene ring making it in trans like position so the resultant dipole moment decreases
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Priyanshu kumar Best Answer

Due to Steric inhibition of resonance lone pair of Nitrogen in 2nd compound does not participate in resonance. No resonance means no charge gets developed...so option A is correct Check this👇
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im not able to form dipole in both structures. kindly show me how dipole is formed in these qs.
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sourav resonating structure banenge toh charge separation honge ...means dipole moment honge
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and how to compare dipole moment between two resonating structures
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jitna jyada resonance honge utna jyada...kyunki dipole moment= charge × distance
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so tmhe 2 compound me aayenge compare karne check krna kisme kitna resonance hai
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if after charge separation aromatic compounds is formed then it has maxm dipole moment
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