IIT JAM
Ankur Rao Asked a Question
January 22, 2021 12:29 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

Solve xe 4x+ 2y = e dx dx2 (a) y = c.x1 + c,x2 + x? ex (b) y = c,x - c,x2 + x2 ex (c) y = c.xl - c.x2 -x2 ex (d) y = c,x + c,x2 + x ex

Solve xe 4x+ 2y = e dx dx2 (A) y = C.x1 + C,x2 + X? ex (B) y = C,x - C,x2 + x2 ex (C) y = C.Xl - c.x2 -x2 ex (D) y = C,x + C,x2 + x ex
  • 2 Answer(s)
Answer Now
  • like-1
  • 1 Likes
  • 10 Comments
  • Shares
  • Priyadarshan Choursiya
    see attachment
    • cropped3893051749187273386.jpg
    Likes(0) Reply(0)
  • Satpal singh
    and basis functions in C.F. are same in both options
    Likes(0) Reply(0)
  • Satpal singh
    bcoz if u see P.I. of both options are same
    Likes(0) Reply(0)
  • Satpal singh
    otherwise logically a , b are correct
    Likes(0) Reply(0)
  • Satpal singh thankyou
    then for go for option 1
    Likes(0) Reply(0)
  • Satpal singh Best Answer
    see this pdf
    • 22 jan 1.pdf
    Likes(0) Reply(0)
  • Satpal singh
    bcoz we can assume -c2 as new constant
    Likes(0) Reply(1)
    Ankur Rao
    it is in single correct.
  • Satpal singh
    option a , b are correct
    Likes(0) Reply(0)
  • Satpal singh
    see the attachment
    • cropped4118797796980161659.jpg
    Likes(0) Reply(0)
  • Satpal singh
    see the attachment
    • cropped8955642701630086297.jpg
    Likes(0) Reply(0)