Thanveer posted an Question
October 23, 2020 • 12:38 pm 5 points
  • IIT JAM
  • Physics (PH)

Solve ydx - xdy + logxdx = 0. (a) y=cx' + (1- logx) (b) y = cx- (1 +logx) (c) y logx + cx (d) y = logx - cx

Solve ydx - xdy + logxdx = 0. (A) y=cx' + (1- logx) (B) y = Cx- (1 +logx) (C) y logx + cx (D) y = logx - CX

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    Sheya maurya best-answer

    firstly divide the both side of the equation by DX. up next substitute y = VX and dY/dx= v+xdv/dx. solve this and at last put the value v = Y/x

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