Karnan posted an Question
November 01, 2020 • 13:41 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Solvolysis of the optically active compound x gives, mainly: meo mc acok acoh ots me a) meo me oa me opiically active) b) mco me oac me (oplically activ ) c) me

Solvolysis of the optically active compound X gives, mainly: MeO Mc AcOK AcOH OTs Me a) Meo Me OA Me opiically active) b) McO Me OAC Me (oplically activ ) c) Meo Me OAc Me oplically inactiv) (Raceic d) MeO Me OAc Me (oplically mactiv c (Racemic

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    Dinesh khalmaniya 1 Best Answer

    option C. here NGP of benzene ring takes place so stereochemistry of attaching nucleophilic doesn't change

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    got it??

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    Yes sir

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    Priyanshu kumar

    Option C is correct Explanation:- -OTS is a good leaving group. So after departure of the leaving group (OTS-) a carbocation will form whose geometry is planer so there is two possibility of attacking the nucleophile ( OAC- furnished by AcOK) : 1) above the plane and 2) down the plane . So a racimic mixture will be formed which is optically inactive. If the nucleophile attacked the carbon centre from down the group then the configuration of the centre will either of the + or - then the racimic mixture was not obtained .

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    got this aswin?

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    please mark the answer aswin

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