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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
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ma'am, please explain these two steps
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in the second equation, you raised the LHS by 403 doesn't that change the remainder. if it is some result then please forward it to me.
Choosek=2015 and x=5, gcd(k,ϕ(11))=gcd(2015,10)=5, then we conclude that n105=n2≡1(mod11) However, it doesn't mean that all the solution of n2≡1(mod11) is the solution to the original problem. It just claims that the solution of the original system satisfy n2≡1(mod11) since 11 is a
I am extremely sorry ma'am but I didn't get you fully.
1^403= 1
in this the second step you did square but from 3rd you started multiplying can you pls explain why is so.