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Shivani Keshri posted an Question
November 06, 2021 • 03:55 am 30 points
  • IIT JAM
  • Mathematics (MA)

. suppose a 1s a real square matrix of odd order such that a+ a = 0. prove that a is singular. [2009 6 marks] 1. let a be an nxn matrix such that a" = 0 and a #

. Suppose A 1s a real square matrix of odd order such that A+ A = 0. Prove that A is singular. [2009 6 Marks] 1. Let A be an nxn matrix such that A" = 0 and A #0. Show that there exists a vector ve R" such that u, Av,..., A*v forms a basis for R". 6o-pe [2009: 6 Marks] S11 ooIT

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  • Anonymous User

    10 A^T =-A | A^T |=|-A| |A^T |=-|A| since order of A is odd |A|=-|A| |A|=0

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