Shivani keshri Asked a Question
November 5, 2021 10:25 pmpts 30 pts
. Suppose A 1s a real square matrix of odd order such that A+ A = 0. Prove that A is singular. [2009 6 Marks] 1. Let A be an nxn matrix such that A" = 0 and A #0. Show that there exists a vector ve R" such that u, Av,..., A*v forms a basis for R". 6o-pe [2009: 6 Marks] S11 ooIT
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  • Kanika goswami 1 thankyou
    Check attachment.
    • cropped2483471964541405258.jpg
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  • Ishu 1
    10 A^T =-A | A^T |=|-A| |A^T |=-|A| since order of A is odd |A|=-|A| |A|=0
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