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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Physics (PH)
T'2) 2 a dlane wave solution of the electromagnetic wave equation is 23. e = ye cos (ot kx + a) +z e cos (ot - kx + b) oz under what conditions is this light wa
T'2) 2 A Dlane wave solution of the electromagnetic wave equation is 23. E = yE COs (ot kx + a) +z E cos (ot - kx + B) oz Under what conditions is this light wave circularly polarized ? (A) B-a = #2- (B) B- a = and E E (D) B- a = t and E 2E o (C) a B and E, = E ntion imnlins the ahsence of magnet
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Dhairya sharma
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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Somnath Best Answer
When both the two components of electric field have same amplitude and their phase difference is π/2 then the electric field will be circularly polarized. So here E will be circularly polarized if Eoy = Eoz and phase difference [(wt-kx+B)-(wt-kx+A)]=+or-π/2 i.e, B-A=+or-π/2 Thus the answer is option B.
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ya, sir i get the same result. but in my book option given to be c. so iam confused.
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