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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Ram Prasath posted an Question
June 02, 2021 • 14:14 pm
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30 points
30 points
- IIT JAM
- Physics (PH)
T/2 sin x cosx ex. dx equals coss x +3 cosx +2 sol. put cos x = t, then tdt tdt f3t+2t1(t+2) nc =[2 log (t+2)- log(t+ 1)] =2 log 3-log 2-2log 2+ log1 = log (9/8
t/2 sin x cosx Ex. dx equals coss X +3 cosx +2 Sol. Put cos x = t, then tdt tdt F3t+2t1(t+2) nc =[2 log (t+2)- log(t+ 1)] =2 log 3-log 2-2log 2+ log1 = log (9/8) : friends in question there is 0 and pi by 2 limited but in answer it changed in to 0 and 1 . how?
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Durga madhab jani
Now limit become 0 to 1
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but the lower limit is 0 so isn't it supposed to be 1
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yes put a -ve sign and change the limit from 1to0
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u mean the 0 will be 1 and pi by 2 will be 0?
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no brother while changing the limit put a -ve sign to the whole integration
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oh thank you for ur response
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Durga madhab jani
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cos 0= 1
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Durga madhab jani
i.e cos(π/2)=0
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Durga madhab jani
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when we change the cosine function into a variable then limit also changed
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Avijeet banerjee
by using a property of definite integral ,limits are interchanged