T/2 sin x cosx ex. dx equals coss x +3 cosx +2 sol. put cos x = t, then tdt tdt f3t+2t1(t+2) nc =[2 log (t+2)- log(t+ 1)] =2 log 3-log 2-2log 2+ log1 = log (9/8

t/2 sin x cosx Ex. dx equals coss X +3 cosx +2 Sol. Put cos x = t, then tdt tdt F3t+2t1(t+2) nc =[2 log (t+2)- log(t+ 1)] =2 log 3-log 2-2log 2+ log1 = log (9/8) : friends in question there is 0 and pi by 2 limited but in answer it changed in to 0 and 1 . how?