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Vanshika Asked a Question
July 19, 2020 3:02 pmpts 30 pts
Frequency of A.C., n = 50 Hz time period T = Time in which current changes from peak value (i) to zero (i) = 40 50 200S 300 1 S. 50 n 1 1 1 200 i.e., AT = S. then Ai = change in current e - 0 -1 =-1 A. mean induced e.m.f., Ai At e =-M- =-1.5 -1 = 300 V. 1/200
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  • Ruby negi Best Answer
    as u posted only solution so it is difficult to answer so correctly. by the solution I can only say that the given current is ac means sinosidal , and u know the graph of sine, it ...
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    Ruby negi
    for any doubt
  • Chandra dhawan thankyou
    see this attached file...
    • cropped525150364.jpg
    Likes(1) Reply(3)
    Chandra dhawan
    see
  • Mahak thankyou
    time changes from peak to zero valcue in 1/4 period of time that is t/4
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  • Vaishali sharma
    see attached
    • cropped2409375802813640758.jpg
    • cropped2422815951819489535.jpg
    • cropped8914237594417784515.jpg
    Likes(1) Reply(3)
    Vaishali sharma
    they will help u
  • Chandra dhawan
    see this daigram
    • cropped-449689622.jpg
    Likes(1) Reply(2)
    Chandra dhawan
    see attached file
  • Chandra dhawan
    yes dear time change from peak to zero value in 1/4 period of time so we take for this 1/4
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  • Chandra dhawan
    see this example also.. it's very helpful for you
    • cropped-1002270631.jpg
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  • Deepak singh
    time change from peak to zero value in 1/4 period of time so we take for this 1/4
    Likes(1) Reply(0)
  • Chandra dhawan
    hope you got it dear
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