IIT JAM Follow
July 19, 2020 3:02 pm 30 pts
Frequency of A.C., n = 50 Hz time period T = Time in which current changes from peak value (i) to zero (i) = 40 50 200S 300 1 S. 50 n 1 1 1 200 i.e., AT = S. then Ai = change in current e - 0 -1 =-1 A. mean induced e.m.f., Ai At e =-M- =-1.5 -1 = 300 V. 1/200
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as u posted only solution so it is difficult to answer so correctly. by the solution I can only say that the given current is ac means sinosidal , and u know the graph of sine, it ...
Ruby negi
for any doubt
• Chandra dhawan
see this attached file...
Chandra dhawan
see
• Mahak
time changes from peak to zero valcue in 1/4 period of time that is t/4
• Vaishali sharma
see attached
Vaishali sharma
they will help u
• Chandra dhawan
see this daigram
Chandra dhawan
see attached file
• Chandra dhawan
yes dear time change from peak to zero value in 1/4 period of time so we take for this 1/4
• Chandra dhawan
see this example also.. it's very helpful for you
• Deepak singh
time change from peak to zero value in 1/4 period of time so we take for this 1/4